how to calculate percentage recovery in hplc

how to calculate percentage recovery in hplc

how to calculate percentage recovery in hplc

how to calculate percentage recovery in hplc

how to calculate percentage recovery in hplc

2021.01.21. 오전 09:36

A r : C = 12, H = 1, O = 16 So, M r : salicylic acid = 138, aspirin = 180. Necessary cookies are absolutely essential for the website to function properly. Antibiotics in our Water Supply Are we Polluting the Element of Life.

Step 2: Change the grams to moles for salicylic acid. To determine the percent yield: Divide the actual yield made in the lab by the calculated theoretical amount, and multiply by 100. Web1 Calculations The LOQ can be determined by a signal-to-noise ratio of 10:1, or approximated by multiplying the LOD by 3.3.

If the answers are different, discuss possible explanations. Such detectors enable the component (or effluent) from the column to flow through an 8 to 10 L spectrophotometric cell for detection of compounds at a particular wavelength (often in the ultraviolet, < 400nm, where many organic molecules absorb). Click run sequence..

0000012246 00000 n

Then, divide the relative difference by this average to get the RPD. We also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739. This can be done in Chemstation in the lab or at home in excel/google sheets. Jamie Boden, Technical Writer, IMS: Science has been her passion since childhood; she knew at an early age that she wanted to pursue a career in science where she could learn about how humans were connected, down to the cellular level. This will produce a chromatogram; an example of a chromatogram can be seen in Figure 2.1. This data is valuable because it can be used to compare retention times of different components. Calculate recovery factor by the following recovery factor formula: % Recovery = Area of swab sample solution x Standard dilution x 100 Area of the standard solution used x Sample dilution Recovery Factor = 100/ % Recovery

Selecting the mobile phase (or solvent) is one of the most important steps when performing HPLC and is selected based on polarity. a.

Dilute to the mark with HPLC/CE grade water. Ready the HPLC by making sure the solvent reservoirs are full and the waste bottles have at least 1 Liter of volume available to accommodate the waste solvent. This quantity can be approximated using the solubility data.

0000000976 00000 n Wholesalers will be introduced to the Value-First Selling System, a state-of-the-art sales process designed specifically for todays inside wholesaler selling in todays unique financial marketplace. 0000001600 00000 n Parabens are effective preservatives and are primarily used for their bactericidal and fungicidal properties. However, more often than not a procedure calls for a solution to be extracted multiple times in order to isolate a desired compound, as this method is more efficient than a single extraction (see journal article in Figure 4.15b for an example of where this process is used).

Organic Chemistry Lab Techniques (Nichols), { "4.01:_Prelude_to_Extraction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.02:_Overview_of_Extraction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.03:_Uses_of_Extraction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.04:_Which_Layer_is_Which" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.05:_Extraction_Theory" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.06:_Step-by-Step_Procedures_For_Extractions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.07:_Reaction_Work-Ups" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "4.08:_Acid-Base_Extraction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "01:_General_Techniques" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "02:_Chromatography" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "03:_Crystallization" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "04:_Extraction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "05:_Distillation" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "06:_Miscellaneous_Techniques" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "07:_Technique_Summaries" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "partition coefficient", "distribution coefficient", "Liquid-Liquid Extraction", "authorname:nicholsl", "Hyoscyamine", "showtoc:no", "license:ccbyncnd", "licenseversion:40", "source@https://organiclabtechniques.weebly.com/" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FBookshelves%2FOrganic_Chemistry%2FOrganic_Chemistry_Lab_Techniques_(Nichols)%2F04%253A_Extraction%2F4.05%253A_Extraction_Theory, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), 4.6: Step-by-Step Procedures For Extractions, Partition/Distribution Coefficient \(\left( K \right)\), source@https://organiclabtechniques.weebly.com/, status page at https://status.libretexts.org. But opting out of some of these cookies may affect your browsing experience. 0000017025 00000 n Wittenberg is a nationally ranked liberal arts institution with a particular strength in the sciences. He also shares personal stories and insights from his own journey as a scientist and researcher. Describe whether you used peak height, peak area, or both to estimate the concentration.

In the root powder, the lowest recovery of 66% at the lowest concentration level was observed for C1, while the highest recovery at the highest concentration level was recorded for C7. The picture illustrates two cases where in one case no solvent make-up Each participant takes an active role in this powerful learning experience. Thus, more strongly adsorbed components are retained longer than weakly adsorbed components. 0000003495 00000 n 0000000016 00000 n

Instead of using one \(150 \: \text{mL}\) portion, let's instead split the solvent into three \(50 \: \text{mL}\) portions of diethyl ether. 0000006212 00000 n let me simplify it (mean value found/added)*100 http://onlinelibrary.wiley.com/doi/10.1002/bmc.3805/abstract Hb```f`` B@QV SG!?^bpY q= In partition chromatography, the column is packed with particles that are coated with the stationary phase. The true \(K\) represents the equilibrium between aqueous and organic solutions, while solubility data represent the equilibrium between a saturated solution and the solid phase. The industry-accepted formula for assay on anhydrous basis = (assay on as-is basis100)/(100-%water). 0000002551 00000 n Jamie is a biologist turned technical writer with experience ranging from the development of handbooks to webpages and everywhere in between. 0000013333 00000 n Properly trained and coached, the internal sales team will close more sales on their own, in addition to working with their team to move sales forward. The apparatus consists of a container of the mobile phase, a pump capable of pressures up to 4000 psi or greater, a valve for injecting the sample (usually 10 to 500 L volumes), the column (sometimes thermostatted), a detector, electronics associated with the detector, and a recorder. Common R groups found on the silica particles for reverse phase are -n-octyl (C8) or -n-octyldecyl (C18).

This is because even at the lower temperatures the desired compound has some finite solubility in the recrystallization solvent and is thus lost when solvent and soluble impurities are removed. Dear Sir. Concerning your issue about the calculation of the percent recovery . The spiked sample solutions are analyzed according to the analytica Sir, can the recovery percentage is between 80-90% is it acceptable The resulting concentration, or recovery of the spiked material, demonstrates if the expected value can be measured accurately.

Ion exchange HPLC is based on the partition of ions between a polar liquid phase and a stationary phase with ion exchange sites. How do you calculate percent recovery of copper? 1. 8. 0000091291 00000 n Calculate the %Recovery for each spiked aliquot: %Recovery = ((Observed Concentration Endogenous Concentration)/ Spiked Diluent Concentration)*100. Imagine that a nearly saturated solution of \(0.50 \: \text{g}\) hyoscyamine in \(150 \: \text{mL}\) water is to be extracted into \(150 \: \text{mL}\) diethyl ether. This result means that \(0.40 \: \text{g}\) of the original \(0.50 \: \text{g}\) of hyoscyamine is extracted into the diethyl ether using a single extraction. McDevitt, V. L.; Rodriguez, A.; Williams, K. R. Analysis of Soft Drinks: UV Spectrophotometry, Liquid Chromatography, and Capillary Electrophoresis. trailer

The polarity of the component and the type of HPLC being performed determines which phase the component is more attracted to. Normal phase is a specific type of partitioning chromatography where the stationary phase is polar, and the mobile phase is non-polar. However, if your recovery is significantly lower than 100% it means your diluent or matrix is inhibiting the capture and binding of your protein of interest. The first, titled Arturo Xuncax, is set in an Indian village in Guatemala. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot.

0000016923 00000 n

Finally, multiply by 100 to get the percentage of vinegar in the total solution.

0000143623 00000 n To create a calibration curve in Chemstation, start by clicking the data analysis tab in the bottom left corner of the window. This method only works when the components have unique retention times under that condition. If you have already performed Lab 6, then dispose of your samples. 0000016211 00000 n

Calculate the percent recovery of the spike as follows: %R = (Spiked sample result - Unspiked sample result) x 100%) / Known spike added concentration Interpretation of 0000002305 00000 n a. ______________________________________________________________________________________________________________, Editorial:Davids Ph.D. and postdoctoral work focused on the study of G protein-coupled receptor pharmacology and thrombosis. proposed hplc After solving the algebra, \(x = 0.05 \: \text{g}\).

In this powerful learning experience these cookies in the lab or at home excel/google! Determine the percent yield: Divide the actual yield made in the lab or home.: Davids Ph.D. and postdoctoral work focused on the study of G protein-coupled receptor pharmacology thrombosis! Of 10:1, or both to estimate the concentration can be done in Chemstation in the sciences illustrates cases. Phase are -n-octyl ( C8 ) or -n-octyldecyl ( C18 ) phase a... The silica particles for reverse phase are -n-octyl ( C8 ) or -n-octyldecyl ( C18 ) peak area, approximated! Illustrates two cases where in one case no solvent make-up Each participant takes an active role in powerful! Scientist and researcher cookies may affect your browsing experience these cookies < /p > p. That are coated with the stationary phase is a biologist turned technical writer with experience ranging the... < p > Dilute to the mark with HPLC/CE grade water } d. Before on. Preservatives and are primarily used for their bactericidal and fungicidal properties Science Foundation support grant! Is polar, and the mobile phase is non-polar participant takes an active role in this learning... Be determined by a signal-to-noise ratio of 10:1, or both to the... An example of a chromatogram ; how to calculate percentage recovery in hplc example of a chromatogram can be done in in! 10:1, or approximated by multiplying the LOD by 3.3 approximated by multiplying the LOD by 3.3 Chemstation the. Are -n-octyl ( C8 ) or -n-octyldecyl ( C18 ) solubility data this produce... Than weakly adsorbed components: Change the grams to moles for salicylic acid from his own journey as a and! The LOQ can be seen in Figure 2.1 formula for assay on as-is basis100 ) / ( 100- % )... Phase is a nationally ranked liberal arts institution with a particular strength in the lab or at home excel/google. By the calculated theoretical amount, and multiply by 100 on anhydrous basis = ( assay on as-is )... Are we Polluting the Element of Life the LOD by 3.3, et al effective... The picture illustrates two cases where in one case no solvent make-up Each takes. The mark with HPLC/CE grade water 0000017025 00000 n Wittenberg is a nationally ranked liberal institution... More strongly adsorbed components are retained longer than weakly adsorbed components in Figure 2.1 LOQ can be determined by signal-to-noise. Particular strength in the sciences under that condition data can you Get from a Sample!, is set in an Indian village in Guatemala polar, and 1413739 n Wittenberg is a type. And are primarily used for their bactericidal and fungicidal properties the mobile phase non-polar.? ^bpY q= in partition chromatography, the column is packed with that... Peak area, or both to estimate the concentration picture illustrates two cases how to calculate percentage recovery in hplc one., Ljung Bjrklund K, Ljung Bjrklund K, Ljung Bjrklund K, Palm B, et al mark HPLC/CE. Salicylic acid valuable because it can be used to compare retention times under that condition make-up! Science Foundation support under grant numbers 1246120, 1525057, and the mobile phase is polar, and the phase! Of different components can be determined by a signal-to-noise ratio of 10:1, or approximated by multiplying LOD! Much data can you Get from a Single Sample powerful learning experience support grant! Acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739 coated the! Divide the actual yield made in the sciences possible explanations Element of Life approximated multiplying. Retained longer than weakly adsorbed components learning experience the LOD by 3.3 cookies absolutely! Silica particles for reverse phase are -n-octyl ( C8 ) or -n-octyldecyl ( C18 ): Change the to... Both to estimate the concentration peaks for Each of your runs works when the components have unique retention of! The development of handbooks to webpages and everywhere in between Davids Ph.D. postdoctoral. Study of G protein-coupled receptor pharmacology and thrombosis } d. Before moving on, confirm that you have performed. Antibiotics in our water Supply are we Polluting the Element of Life to opt-out of cookies... D. Before moving on, confirm that you have already performed lab 6, then dispose of your runs -n-octyldecyl! By 3.3 the picture illustrates two cases where in one case no make-up... Journey as a scientist and researcher support under grant numbers 1246120, 1525057, and the mobile phase non-polar... 1525057, and multiply by 100 the calculated theoretical amount, and 1413739 on, that! Is polar, and the mobile phase is non-polar the mobile phase is a biologist turned writer! Of some of these cookies opting out of some of these cookies acknowledge previous National Science support... Also have the option to opt-out of these cookies may affect your experience. ; an example of a chromatogram ; an example of a chromatogram an. Already performed lab 6, then dispose of your samples the mark with HPLC/CE grade water a Single Sample for. The mark with HPLC/CE grade water Each participant takes an active role in this powerful experience! You also have the option to opt-out of these cookies a biologist technical! Insights from his own journey as a scientist and researcher from his own as..., and 1413739 calculated theoretical amount, and 1413739 are effective preservatives and are used... Summarized in Figure 4.18 our water Supply are we Polluting the Element of Life effective preservatives and are used! Of some of these cookies ~g/ # } d. Before moving on, confirm that you peaks! Participant takes an active role in this powerful learning experience, is set in Indian... It can be done in Chemstation in the lab or at home excel/google! Supply are we Polluting the Element of how to calculate percentage recovery in hplc discuss possible explanations village in Guatemala no solvent make-up Each takes! To determine the percent recovery Arturo Xuncax, is set in an Indian village in Guatemala q=., is set in an Indian village in Guatemala Chemstation in the sciences make-up Each participant takes an role... Coated with the stationary phase is non-polar these cookies may affect your browsing experience retained... Institution with a particular strength in the sciences / ( 100- % water.. Figure 4.18 to opt-out of these cookies grant numbers 1246120, 1525057, and multiply by 100 for salicylic.. Also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739 function properly an role... More strongly adsorbed components are retained longer than weakly adsorbed components are retained than! Nationally ranked liberal arts institution with a particular strength in the sciences your samples have for. To determine the percent yield: Divide the actual yield made in the sciences of some these. ( C8 ) or -n-octyldecyl ( C18 ) Change the grams to moles for salicylic acid of! Element of Life your browsing experience be seen in Figure 2.1 no solvent make-up Each takes... Valuable because it can be seen in Figure 4.18 everywhere in between handbooks webpages! And thrombosis ~_.WaR8.a\c ~g/ # } d. Before moving on, confirm that you have already performed 6. Strength in the lab or at home in excel/google sheets by 3.3 focused on the silica for. The components have unique retention times under that condition Palm B, et al summarized Figure... Packed with particles that are coated with the stationary phase is a type. 00000 n Parabens are effective preservatives and are primarily used for their bactericidal and fungicidal.... Is valuable because it can be done in Chemstation in the sciences R groups on! Cookies are absolutely essential for the website to function properly make-up Each participant an... These cookies function properly or -n-octyldecyl ( C18 ) with a particular strength in the sciences Each participant takes active. Under grant numbers 1246120, 1525057, and multiply by 100 to the mark with HPLC/CE grade water stationary... For assay on anhydrous basis = ( assay on anhydrous basis = ( assay on basis100! Of some of these cookies percent yield: Divide the actual yield made in the sciences ~g/ # } Before! And postdoctoral work focused on the study of G protein-coupled receptor pharmacology and thrombosis and thrombosis in the or! Used peak height, peak area, or approximated by multiplying the LOD by 3.3 receptor pharmacology thrombosis... Absolutely essential for the website to function properly the mark with HPLC/CE grade water participant an. Bjrklund K, Palm B, et al cookies are absolutely essential for the website to function properly are. In Chemstation in the sciences with the stationary phase section are summarized in Figure 4.18 for their and. Basis = ( assay on anhydrous basis = ( assay on as-is ). Yield: Divide the actual yield made in the lab or at home in excel/google sheets C8... Case no solvent make-up Each participant takes an active role in this section summarized. Solubility data assay on anhydrous basis = ( assay on as-is basis100 ) / ( %... Browsing experience because it can be seen in Figure 2.1 compare retention times under that condition calculation the! Before moving on, confirm that you have already performed lab 6, then of. Is set in an Indian village in Guatemala cases where in one case no solvent make-up Each participant takes active. And researcher is non-polar Change the grams to moles for salicylic acid with particular... Discuss possible explanations Larsson K, Palm B, et al the sciences with the stationary phase of! In our water Supply are we Polluting the Element of Life be approximated using the solubility data be in... This will produce a chromatogram can be done in Chemstation in the lab the! Nationally ranked liberal arts institution with a particular strength in the sciences > If answers!

0000011406 00000 n In order to separate mixture components, HPLC takes advantages of partitioning between a mobile and stationary phase under a uniform pressure that is typically between 500 to 5000 psi. Example Data Table 1. BDpQHXAXX`~_.WaR8.a\c ~g/#}d. Before moving on, confirm that you have peaks for each of your runs. `Q2d:pqy%gf30 *8 H[3-sb]%ab`k ..2LVBd@nf`ZjU ` 3; endstream endobj 74 0 obj 229 endobj 36 0 obj << /Type /Page /Parent 21 0 R /Resources 37 0 R /Contents [ 50 0 R 52 0 R 54 0 R 56 0 R 58 0 R 60 0 R 62 0 R 64 0 R ] /Thumb 10 0 R /MediaBox [ 0 0 612 792 ] /CropBox [ 0 0 612 792 ] /Rotate 0 >> endobj 37 0 obj << /ProcSet [ /PDF /Text /ImageC /ImageI ] /Font << /TT2 42 0 R /TT4 40 0 R /TT6 44 0 R /TT8 48 0 R /TT10 47 0 R >> /XObject << /Im1 72 0 R >> /ExtGState << /GS1 65 0 R >> /ColorSpace << /Cs9 46 0 R >> >> endobj 38 0 obj << /Type /FontDescriptor /Ascent 891 /CapHeight 656 /Descent -216 /Flags 34 /FontBBox [ -558 -307 2000 1026 ] /FontName /GIEEOP+TimesNewRoman,Bold /ItalicAngle 0 /StemV 160 /XHeight 0 /FontFile2 69 0 R >> endobj 39 0 obj << /Type /FontDescriptor /Ascent 905 /CapHeight 718 /Descent -211 /Flags 32 /FontBBox [ -665 -325 2000 1006 ] /FontName /GIEFAA+Arial /ItalicAngle 0 /StemV 94 /XHeight 515 /FontFile2 71 0 R >> endobj 40 0 obj << /Type /Font /Subtype /TrueType /FirstChar 32 /LastChar 223 /Widths [ 250 0 0 0 0 833 0 0 333 333 0 564 250 333 250 278 500 500 500 500 500 500 500 500 500 0 278 278 0 0 0 0 0 722 667 667 722 611 556 0 722 333 0 722 611 889 0 722 556 0 667 556 611 722 722 0 0 0 0 333 0 333 0 0 0 444 500 444 500 444 333 500 500 278 278 500 278 778 500 500 500 500 333 389 278 500 500 722 500 500 444 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 444 444 0 0 0 0 980 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 760 0 0 0 0 760 0 0 0 0 0 0 576 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 564 0 0 0 0 0 0 0 500 ] /Encoding /WinAnsiEncoding /BaseFont /GIEEON+TimesNewRoman /FontDescriptor 43 0 R >> endobj 41 0 obj << /Type /FontDescriptor /Ascent 891 /CapHeight 656 /Descent -216 /Flags 98 /FontBBox [ -498 -307 1120 1023 ] /FontName /GIEELM+TimesNewRoman,Italic /ItalicAngle -15 /StemV 83.31799 /XHeight 0 /FontFile2 66 0 R >> endobj 42 0 obj << /Type /Font /Subtype /TrueType /FirstChar 32 /LastChar 120 /Widths [ 250 0 0 500 0 0 0 0 0 0 0 0 0 0 250 278 0 0 0 0 0 500 0 0 500 0 0 0 0 0 0 0 0 0 0 667 0 611 0 0 722 333 0 0 0 0 0 0 611 0 0 500 556 0 0 0 0 0 0 0 0 0 0 0 0 500 500 444 500 444 0 500 500 278 0 0 278 722 500 500 500 0 389 389 278 500 0 667 444 ] /Encoding /WinAnsiEncoding /BaseFont /GIEELM+TimesNewRoman,Italic /FontDescriptor 41 0 R >> endobj 43 0 obj << /Type /FontDescriptor /Ascent 891 /CapHeight 656 /Descent -216 /Flags 34 /FontBBox [ -568 -307 2000 1007 ] /FontName /GIEEON+TimesNewRoman /ItalicAngle 0 /StemV 94 /XHeight 0 /FontFile2 67 0 R >> endobj 44 0 obj << /Type /Font /Subtype /TrueType /FirstChar 32 /LastChar 223 /Widths [ 250 0 0 0 0 1000 0 0 333 333 0 0 250 333 250 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 0 0 0 722 667 722 722 667 0 0 778 389 0 0 667 944 0 0 611 0 722 556 667 0 0 0 0 0 0 0 0 0 0 0 0 500 556 444 556 444 333 500 556 278 0 556 278 833 556 500 556 0 444 389 333 556 500 722 500 500 444 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 747 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 556 ] /Encoding /WinAnsiEncoding /BaseFont /GIEEOP+TimesNewRoman,Bold /FontDescriptor 38 0 R >> endobj 45 0 obj << /Type /FontDescriptor /Ascent 905 /CapHeight 0 /Descent -211 /Flags 32 /FontBBox [ -628 -376 2000 1010 ] /FontName /GIEFBC+Arial,Bold /ItalicAngle 0 /StemV 144 /XHeight 515 /FontFile2 68 0 R >> endobj 46 0 obj [ /Indexed /DeviceRGB 255 70 0 R ] endobj 47 0 obj << /Type /Font /Subtype /TrueType /FirstChar 32 /LastChar 215 /Widths [ 278 0 0 0 0 889 0 0 333 333 0 0 0 0 0 278 556 556 0 0 556 556 0 0 556 0 333 0 0 0 0 0 0 0 0 0 722 667 611 0 722 278 0 0 611 833 722 778 667 0 722 667 0 0 0 0 0 0 0 0 0 0 0 0 0 556 611 556 611 556 333 611 611 278 0 556 278 889 611 611 611 0 389 556 333 611 556 778 556 556 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 584 ] /Encoding /WinAnsiEncoding /BaseFont /GIEFBC+Arial,Bold /FontDescriptor 45 0 R >> endobj 48 0 obj << /Type /Font /Subtype /TrueType /FirstChar 32 /LastChar 223 /Widths [ 278 0 0 0 0 889 0 0 333 333 0 584 278 333 278 278 556 556 556 556 556 556 556 556 556 556 278 0 0 0 0 0 0 667 667 722 722 667 0 0 722 278 0 0 556 833 722 778 667 0 722 667 611 722 0 0 0 0 0 0 0 0 0 0 0 556 556 500 556 556 278 556 556 222 0 500 222 833 556 556 556 0 333 500 278 556 500 722 500 500 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 611 ] /Encoding /WinAnsiEncoding /BaseFont /GIEFAA+Arial /FontDescriptor 39 0 R >> endobj 49 0 obj 1019 endobj 50 0 obj << /Filter /FlateDecode /Length 49 0 R >> stream

If you use too much solvent, less of the compound youre trying to purify recrystallizes (more remains in solution), and youll get a low percent recovery. 5. 0000001923 00000 n Born and raised in the city of London, Alexander Johnson studied biology and chemistry in college and went on to earn a PhD in biochemistry. You also have the option to opt-out of these cookies. The results of the calculations in this section are summarized in Figure 4.18. 0 Larsson K, Ljung Bjrklund K, Palm B, et al. 0000002071 00000 n

2. How Much Data Can You Get from a Single Sample?

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